Python super() – Python 3 super()

Filed Under: Python

Python super() function allows us to refer to the parent class explicitly. It’s useful in case of inheritance where we want to call super class functions.

Python super

To understand about python super function, you have to know about Python Inheritance. In Python Inheritance, the subclasses inherit from the superclass.

Python super() function allows us to refer the superclass implicitly. So, Python super makes our task easier and comfortable. While referring the superclass from the subclass, we don’t need to write the name of superclass explicitly. In the following sections, we will discuss python super function.

Python super function example

At first, just look at the following code we used in our Python Inheritance tutorial. In that example code, the superclass was Person and the subclass was Student. So the code is shown below.

class Person:
    # initializing the variables
    name = ""
    age = 0

    # defining constructor
    def __init__(self, person_name, person_age): = person_name
        self.age = person_age

        # defining class methods

    def show_name(self):

    def show_age(self):

# definition of subclass starts here
class Student(Person):
    studentId = ""

    def __init__(self, student_name, student_age, student_id):
        Person.__init__(self, student_name, student_age)
        self.studentId = student_id

    def get_id(self):
        return self.studentId  # returns the value of student id

# end of subclass definition

# Create an object of the superclass
person1 = Person("Richard", 23)
# call member methods of the objects
# Create an object of the subclass
student1 = Student("Max", 22, "102")

In the above example, we have called parent class function as:

Person.__init__(self, student_name, student_age) 

We can replace this with python super function call as below.

super().__init__(student_name, student_age)

The output will remain the same in both the cases, as shown in the below image.

python super, python 3 super

Python 3 super

Note that the above syntax is for python 3 super function. If you are on python 2.x versions, then it’s slightly different and you will have to do the following changes:

class Person(object):
        super(Student, self).__init__(student_name, student_age)

The first change is to have object as the base class for Person. It’s required to use the super function in Python 2.x versions. Otherwise, you will get the following error.

Traceback (most recent call last):
  File "", line 40, in <module>
    student1 = Student("Max", 22, "102")
  File "", line 25, in __init__
    super(Student, self).__init__(student_name, student_age)
TypeError: must be type, not classobj

The second change in the syntax of the super function itself.

As you can see that python 3 super function is a lot easier to use and the syntax is also clean looking.

Python super function with multilevel inheritance

As we have stated previously that Python super() function allows us to refer the superclass implicitly.

But in the case of multi-level inheritances which class will it refer? Well, Python super() will always refer the immediate superclass.

Also Python super() function not only can refer the __init__() function but also can call all other function of the superclass. So, in the following example, we will see that.

class A:
    def __init__(self):
        print('Initializing: class A')

    def sub_method(self, b):
        print('Printing from class A:', b)

class B(A):
    def __init__(self):
        print('Initializing: class B')

    def sub_method(self, b):
        print('Printing from class B:', b)
        super().sub_method(b + 1)

class C(B):
    def __init__(self):
        print('Initializing: class C')

    def sub_method(self, b):
        print('Printing from class C:', b)
        super().sub_method(b + 1)

if __name__ == '__main__':
    c = C()

Let’s see the output of above python 3 super example with multi-level inheritance.

Initializing: class C
Initializing: class B
Initializing: class A
Printing from class C: 1
Printing from class B: 2
Printing from class A: 3

So, from the output we can clearly see that the __init__() function of class C had been called at first, then class B and after that class A. Similar thing happened by calling sub_method() function.

Why do we need Python super function

If you have previous experience in Java language, then you should know that the base class is also called by a super object there. So, this concept is actually useful for the coders. However, Python also keeps the facility for the programmer to use superclass name to refer them. And, if your program contains multi-level inheritance, then this super() function is helpful for you.

So, that’s all about python super function. Hopefully, you understood this topic. Please use the comment box for any query.

You can checkout complete python script and more Python examples from our GitHub Repository.

Reference: Official Documentation


  1. Robert Cox says:

    Please revisit your example code on page:

    i.e., your definition of class Person
    uses class scope variable definitions that are not subsequently used.

    class Person:
    # initializing the variables
    name = “” <<<<<this is class scope
    age = 0 <<<<<this is class scope

    The same is true for class student:
    class Student(Person):
    studentId = "" <<<<<this is class scope


  2. Ajay says:

    Hi, Can you explain the submethod execution flow

    Printing from class C: 1
    Printing from class B: 2
    Printing from class A: 3

    if the submethod of C is executing first, Output should be : Printing from class C: 1
    Since def sub_method(self, b):
    print(‘Printing from class C:’, b)
    super().sub_method(b + 1)

    Plzz Explain

  3. Anupam says:

    This is such a neat and easy-to-follow explanation. Thank you!

  4. klenexb says:

    why this is not working

    class FrameApp(Frame):
    def __init__(self,master):

  5. Arun says:

    Person.__init__(self, student_name, student_age)

    super().__init__(student_name, student_age)

    calling parent class using ‘super()’, no need to specify ‘self’. Please explain the reason.

  6. Seth says:

    Whenever I use super().__init__( *args ) I’m greeted with the error TypeError: object.__init__() takes no parameters. Please help. I need to know why this happens and how to prevent it.

    1. Pankaj says:

      __init__() function doesn’t take any arguments. So if you try to provide it, then the error will be thrown.

      1. pranav says:

        it can take argument pankaj, it is a constructor and can take , only thing is that it doesn’t have a return type .
        thanks and regard

  7. eric0109 says:

    what a clear presentation

  8. Gah says:

    That’s not multiple inheritance – that’s multiple levels of inheritance.

    Multiple inheritance is

    class C(A,B):

    1. Pankaj says:

      Yes, you are right, I mistakenly mentioned them as multiple inheritances. I have correct the title of that section.

      1. vikas shrivastava says:

        class A(object):

        def __init__(self):
        print(“Inside A inheritance”)

        class B(object):
        def __init__(self):
        print(“Inside B inheritance”)

        class C(A, B):
        def __init__(self):
        print(“Inside C inheritance”)

        obj = C()

        How can i call Class B contructor in Class C without multiple level Inheritance ?

        1. Arun says:

          This can be achieved by multiple inheritance as below:

          class A(object):
          def __init__(self):
          print(‘Inside A inheritance’)

          class B(object):
          def __init__(self):
          print(‘Inside B inheritance’)

          class C(A, B):
          def __init__(self):
          print(‘Inside C inheritance’)

          obj = C()

Comments are closed.

Generic selectors
Exact matches only
Search in title
Search in content